CUET Mathematics - The feasible reason for the constraints x ≥ 0, x + y ≤ 1 and x - y ≤ 1, is situated in : (A) I and II quadrant only (B) I Quadrant (C) II and IV Quadrant (D) IV Quadrant (E) I , II , III and IV Quadrant Choose the correct answer from the option given below : | PYQs + Solutions

CUET Mathematics 2023 7 June Shift 1

Applied Mathematics

Medium

A , D only

B , D only

B , c only

A , C only

✅ Correct Option: 2

Related questions:

25 May Shift 1

The maximum value of $Z = 3x + y$ subject to the constraints $x + y \leq 30, 2x + y \leq 40, x, y \geq 0$ is

22 May Shift 3

If objective function $Z = 20x + 30y$ of an LPP is subject to the constraints $3x + 4y \geq 12$ , $4x + y \geq 4$ , $x \geq 0, y \geq 0$ , then Z has :

(A) Min at (0, 4)

(B) Max at (0, 4)

(D) Max at (4, 0)

(E) Min at $\left(\frac{4}{13}, \frac{36}{13}\right)$

Choose the correct answer from the options given below :

30 May Shift 3

Corner points of the feasible region for an LPP are : (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). Let $z = 4x + 6y$ be the objective function. Then, Max z $-$ Min z is equal to :

CUET Mathematics 2023 7 June Shift 1 PYQs

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