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Matrix A=[0a54b−1c10]A = \begin{bmatrix} 0 & a & 5 \\ 4 & b & -1 \\ c & 1 & 0 \end{bmatrix} is skew - symmetric, then the values of a, b c are :

Solution

✅ Correct Option: 1

For skew-symmetric matrix: AT=−AA^T = -A, meaning aij=−ajia_{ij} = -a_{ji} and diagonal entries are 0.

Diagonal: b=0b = 0.

a12=−a21a_{12} = -a_{21}: a=−4a = -4.

a13=−a31a_{13} = -a_{31}: 5=−c⇒c=−55 = -c \Rightarrow c = -5.

So a=−4,b=0,c=−5a = -4, b = 0, c = -5.

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