Maximum value of Z equals to 40x + 50y subject to constraints , , occurs at
Maximum value of Z equals to 40x + 50y subject to constraints , , occurs at
Solution
✅ Correct Option: 2
Evaluate Z = 40x + 50y at corner points.
At (0, 4): Z = 0 + 200 = 200.
At (2, 3): Z = 80 + 150 = 230 (maximum).
At (3, 0): Z = 120 + 0 = 120.
At (0, 0): Z = 0.
Maximum occurs at (2, 3).
Related questions:
2023: 11 Aug Shift 1
2023: 7 June Shift 1
2022: 25 May Shift 1