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Maximum value of Z equals to 40x + 50y subject to constraints 3x+y≤93x + y \leq 9, x+2y≤8x + 2y \leq 8, x,y≥0x, y \geq 0 occurs at

Solution

✅ Correct Option: 2

Evaluate Z = 40x + 50y at corner points.

At (0, 4): Z = 0 + 200 = 200.

At (2, 3): Z = 80 + 150 = 230 (maximum).

At (3, 0): Z = 120 + 0 = 120.

At (0, 0): Z = 0.

Maximum occurs at (2, 3).

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