Skip to main contentSkip to solution

In an arithmetic progression, if 6 is the third term, the ninth term exceeds the seventh term by 3, then 12 is which term?

Solution

✅ Correct Option: 3

In an arithmetic progression, the 3rd term is 6 and the 9th term exceeds the 7th term by 3.

The general formula for the nth term of an arithmetic progression is:

nth term =a+(n−1)d= a + (n-1)d

where aa is the first term and dd is the common difference.


The 9th term is 2 positions away from the 7th term.

9th term - 7th term =2d= 2d

2d=32d = 3

d=1.5d = 1.5


The 3rd term is 6:

a+(3−1)d=6a + (3-1)d = 6

a+2d=6a + 2d = 6

a+2(1.5)=6a + 2(1.5) = 6

a+3=6a + 3 = 6

a=3a = 3


To find which term is 12:

a+(n−1)d=12a + (n-1)d = 12

3+(n−1)(1.5)=123 + (n-1)(1.5) = 12

(n−1)(1.5)=9(n-1)(1.5) = 9

n−1=6n-1 = 6

n=7n = 7

Therefore, 12 is the 7th term of the arithmetic progression.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question