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X sold an article to Y at a profit of 18%. Later on, Y sold it back to X at a profit of 40%, thereby gaining ₹ 118. How much did X pay for the article originally?

Solution

✅ Correct Option: 4

Let the original price X paid be PP.


When X sold to Y at 18% profit:

X's selling price =P+0.18P= P + 0.18P

=1.18P= 1.18P

This is Y's cost price.


When Y sold back to X at 40% profit:

Y's selling price =1.18P+0.40(1.18P)= 1.18P + 0.40(1.18P)

=1.18P×1.40= 1.18P \times 1.40

=1.652P= 1.652P


Y's profit == Y's selling price −- Y's cost price

=1.652P−1.18P= 1.652P - 1.18P

=0.472P= 0.472P


Y's profit is given as ₹118:

0.472P=1180.472P = 118

P=1180.472P = \dfrac{118}{0.472}

P=250P = 250

Therefore, X originally paid ₹250 for the article.

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