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Alok walks from point P to point Q, which is 6 km away, then turns right and walks for 12 km to point R, again turns right and goes 11 km to point S. What is the distance between points P and S?

Solution

✅ Correct Option: 4

Setting up a coordinate system with P at the origin and the initial direction along the positive x-axis.

P is at (0,0)(0, 0)

Alok walks 6 km to point Q:

Q is at (6,0)(6, 0)


At Q, Alok turns right and walks 12 km to point R.

Turning right from the positive x-direction means moving in the negative y-direction.

R is at (6,−12)(6, -12)


At R, Alok turns right again and walks 11 km to point S.

Turning right from the negative y-direction means moving in the negative x-direction.

S is at (6−11,−12)=(−5,−12)(6 - 11, -12) = (-5, -12)


The distance between P(0,0)(0, 0) and S(−5,−12)(-5, -12) is:

d=(−5−0)2+(−12−0)2d = \sqrt{(-5 - 0)^2 + (-12 - 0)^2}

d=25+144d = \sqrt{25 + 144}

d=169d = \sqrt{169}

d=13d = 13

Therefore, the distance between points P and S is 13 km.

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