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The areas of three adjacent faces of a cuboidal box are 96 cm², 48 cm² and 72 cm², respectively. The volume of the box is

Solution

✅ Correct Option: 2

The three adjacent faces of a cuboid have areas that represent the products of different pairs of dimensions.

For a cuboid with length ll, width ww, and height hh:

l×w=96l \times w = 96

w×h=48w \times h = 48

l×h=72l \times h = 72


Multiplying all three equations:

(l×w)×(w×h)×(l×h)=96×48×72(l \times w) \times (w \times h) \times (l \times h) = 96 \times 48 \times 72

l2×w2×h2=96×48×72l^2 \times w^2 \times h^2 = 96 \times 48 \times 72

(l×w×h)2=96×48×72(l \times w \times h)^2 = 96 \times 48 \times 72


Calculating the right side:

96×48=460896 \times 48 = 4608

4608×72=3317764608 \times 72 = 331776

Therefore:

(l×w×h)2=331776(l \times w \times h)^2 = 331776


Taking the square root of both sides:

l×w×h=331776l \times w \times h = \sqrt{331776}

l×w×h=576l \times w \times h = 576

Since volume =l×w×h= l \times w \times h, the volume of the box is 576576 cm³.

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