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The first and the last terms of an arithmetic progression are 25 and 180, respectively. If the sum of all the terms is 1025, how many terms are there?

Solution

✅ Correct Option: 1

The first term a=25a = 25, last term l=180l = 180, and sum S=1025S = 1025.

For an arithmetic progression, the sum of all terms is:

S=n2×(a+l)S = \dfrac{n}{2} \times (a + l)

where nn is the number of terms.


Substituting the known values:

1025=n2×(25+180)1025 = \dfrac{n}{2} \times (25 + 180)

1025=n2×2051025 = \dfrac{n}{2} \times 205


2050=205n2050 = 205n

n=2050205n = \dfrac{2050}{205}

n=10n = 10


Therefore, there are 10 terms in the arithmetic progression.

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