Simplify : $\dfrac{\sqrt[4]{0.0625}+\sqrt[3]{0.008}+\sqrt{0.09}-1}{\sqrt[3]{62 \cdot 5 \times \sqrt[5]{32}}}$

Let's simplify the numerator first:

$\sqrt[4]{0.0625} = \sqrt[4]{\frac{1}{16}} = \frac{1}{2}$ (since $(\frac{1}{2})^4 = \frac{1}{16}$)

$\sqrt[3]{0.008} = \sqrt[3]{\frac{8}{1000}} = \frac{1}{5}$ (since $(\frac{1}{5})^3 = \frac{1}{125}$)

$\sqrt{0.09} = \sqrt{\frac{9}{100}} = \frac{3}{10}$

So numerator $=\frac{1}{2} + \frac{1}{5} + \frac{3}{10} - 1$

Converting to common denominator in numerator:

$\frac{5}{10} + \frac{2}{10} + \frac{3}{10} - \frac{10}{10}$

$= \frac{10-10}{10}$

$= 0$

Therefore, entire expression $=\frac{0}{\sqrt[3]{62.5} × \sqrt[5]{32}}= 0$

The answer is $0$.