table border-collapse: collapse; margin: 10px 0; th, td border: 1px solid #ccc; text-align: left; padding: 8px; th background-color: #f2f2f2; color: #333; tr:nth-child(even) background-color: #f9f9f9; Match List I with List II Choose the correct answer from the options given below : Option 1: (A) - (III), (B) - (I), (C) - (IV), (D) - (II) Option 2: (A) - (II), (B) - (III), (C) - (I), (D) - (IV) Option 3: (A) - (II), (B) - (IV), (C) - (I), (D) - (III) Option 4: (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

Answer: (A) - (II), (B) - (IV), (C) - (I), (D) - (III). Solution: Time is of the essence. For these questions, just solve one or two equations and match them with the options, and mark the answer then and there! Solving the first equation: √(15x1635-89) Use DMAS - Division, then Multiplication, then Addition, then Subtraction =√(15x32.6-89)=√(489-89)=√400=20 So we know that A-(II), which is either Option 2 or Option 3. Onto the second equation: √(15^2+11x3^2)=√(225+11x9)=√(225+99)=√324=18 Hence, B-(IV), which is Option 3.

Algebra

Indices

Easy

Match List I with List II

	List-I (Expression)		List-II (Absolute Value)
(A)	$\sqrt{15 \times 163 \div 5-89}$	(I)	105
(B)	$\sqrt{15^{2}+11 \times 3^{2}}$	(II)	20
(C)	$\sqrt{8^{2} \times 7 \times 5^{2}-175}$	(III)	10
(D)	$\sqrt{91+\sqrt{70+\sqrt{121}}}$	(IV)	18

Choose the correct answer from the options given below :

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

(A) - (II), (B) - (III), (C) - (I), (D) - (IV)

(A) - (II), (B) - (IV), (C) - (I), (D) - (III)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

✅ Correct Option: 3

Time is of the essence. For these questions, just solve one or two equations and match them with the options, and mark the answer then and there!

Solving the first equation:

$\sqrt{15\times163\div5-89}$

Use DMAS - Division, then Multiplication, then Addition, then Subtraction

$=\sqrt{15\times32.6-89}=\sqrt{489-89}=\sqrt{400}=20$

So we know that A-(II), which is either Option 2 or Option 3.

Onto the second equation:

$\sqrt{15^2+11\times3^2}=\sqrt{225+11\times9}=\sqrt{225+99}=\sqrt{324}=18$

Hence, B-(IV), which is Option 3.

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