JIPMATGeometry > Easy15 cm15 \mathrm{~cm}15 cm20 cm20 \mathrm{~cm}20 cm203 cm20 \sqrt{3} \mathrm{~cm}203 cm303 cm30 \sqrt{3} \mathrm{~cm}303 cm✅ Correct Option: 3Related questions:JIPMAT 2024The points (2,2),(6,3)(2,2),(6,3)(2,2),(6,3) and (4,11)(4,11)(4,11) are vertices of :JIPMAT 2024An equilateral triangle ABC\mathrm{ABC}ABC is inscribed in a circle of radius 203 cm20 \sqrt{3} \mathrm{~cm}203 cm. What is the length of the side of the triangle ?JIPMAT 2022Given below are two statements: Statement I: In △ABC,AB=63 cm,AC=12 cm\triangle A B C, A B=6 \sqrt{3} \mathrm{~cm}, A C=12 \mathrm{~cm}△ABC,AB=63 cm,AC=12 cm and BC=6 cmB C=6 \mathrm{~cm}BC=6 cm, then angle B=90∘B=90^{\circ}B=90∘ Statement II: In △ABC\triangle A B C△ABC, is an isosceles with AC=BCA C=B CAC=BC. If AB2=2AC2A B^{2}=2 AC^{2}AB2=2AC2, Then angle C=90∘C=90^{\circ}C=90∘ In the light of the above statement, choose the correct answer form the question below.