IPMAT IndoreAlgebra > Mediumπ26−1\frac{\pi^2}{6} - 16π2−1π6\frac{\pi}{6}6ππ212\frac{\pi^2}{12}12π2π28\frac{\pi^2}{8}8π2✅ Correct Option: 4Related questions:IPMAT Indore 2019Assume that all positive integers are written down consecutively from left to right as in 1234567891011...... The 6389th digit in this sequence isIPMAT Indore 2025The sum of the first 5 terms of a geometric progression is the same as the sum of the first 7 terms of the same progression. If the sum of the first 9 terms is 24, then the 4th term of the progression isIPMAT Indore 2025If the sum of the first 212121 terms of the sequence: lnab,lnabb,lnab2,lnab2b,…\ln \frac{a}{b}, \ln \frac{a}{b \sqrt{b}}, \ln \frac{a}{b^{2}}, \ln \frac{a}{b^{2} \sqrt{b}}, \ldotslnba,lnbba,lnb2a,lnb2ba,… is lnambn\ln \frac{a^{m}}{b^{n}}lnbnam, then the value of m+nm+nm+n is \qquad