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Let f(x)=a2x2+2bx+cf(x) = a^2x^2 + 2bx + c where, a≠0a \neq 0, b,cb, c are real numbers and xx is a real variable then

Solution

✅ Correct Option: 2

f(x)=a2x2+2bx+cf(x) = a^2x^2 + 2bx + c

In f(x)f(x), we know that a2a^2 will always be positive, ergo, it'll be greater than 0.

Solution figure for IPMAT Indore 2025 MCQ question 14 (Algebra)

Hence, the quadratic function will be U-shaped (opening upward).

Thus, it has a minimum point but no maximum point (goes all the way till infinity).

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