IPMAT Indore 2025 Modern Math > Probability PYQs

$\frac{1}{25}$

$\frac{1}{12}$

$\frac{1}{20}$

$\frac{1}{16}$

$\frac{4}{9}$

$\frac{5}{9}$

$\frac{4}{15}$

$\frac{2}{15}$

$\dfrac{22}{2023}$

$\dfrac{23^2}{{2024}^2}$

$\dfrac{22}{2024}$

$\dfrac{22^2}{{2023}^2}$

$\frac{1}{2}$

$\frac{10}{19}$

$\frac{2}{3}$

$\frac{9}{19}$

5

6

3

7

$f(2) = \frac{1}{13} > f(3)$

$\frac{1}{13} > f(2) > f(3)$

$f(3) > f(2) = \frac{1}{13}$

$f(2) = f(3) = \frac{1}{13}$

$\frac{1}{6}$

$\frac{1}{4}$

$\frac{1}{5}$

$\frac{1}{10}$