IPMAT IndoreAlgebra > Hardπ28\frac{\pi^2}{8}8π2π216\frac{\pi^2}{16}16π2π212\frac{\pi^2}{12}12π2π236\frac{\pi^2}{36}36π2✅ Correct Option: 1Related questions:IPMAT Indore 2019If (1+x−2x2)6=A0+∑r=112Arxr(1 + x - 2x^2)^6 = A_0 + \sum_{r=1}^{12} A_r x^r(1+x−2x2)6=A0+∑r=112Arxr, then the value of A2+A4+A6+⋯+A12A_2 + A_4 + A_6 + \cdots + A_{12}A2+A4+A6+⋯+A12 isIPMAT Indore 2025If the sum of the first 212121 terms of the sequence: lnab,lnabb,lnab2,lnab2b,…\ln \frac{a}{b}, \ln \frac{a}{b \sqrt{b}}, \ln \frac{a}{b^{2}}, \ln \frac{a}{b^{2} \sqrt{b}}, \ldotslnba,lnbba,lnb2a,lnb2ba,… is lnambn\ln \frac{a^{m}}{b^{n}}lnbnam, then the value of m+nm+nm+n is \qquadIPMAT Indore 2022The 3rd ,14th 3^{\text {rd }}, 14^{\text {th }}3rd ,14th and 69th 69^{\text {th }}69th terms of an arithmetic progression form three distinct and consecutive terms of a geometric progression. If the next term of the geometric progression is the nth n^{\text {th }}nth term of the arithmetic progression, then nnn equals ________.