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Suppose a,ba, b and cc are three real numbers such that Max(a,b,c) +(a, b, c) \ + Min(a,b,c)=15(a, b, c) = 15, and Median(a,b,c) −(a, b, c) \ - Mean(a,b,c)=2.(a, b, c) = 2. Then the median of a,ba, b and cc is

Solution

✅ Correct Option: 2

Let the maximum value =M=M

Let the minimum value =m=m

Let the median value =d= d

In a way, we've gotten the 3 numbers (a,b,c)(a, b, c).

Mean=M+m+d3→(1)\text{Mean} = \dfrac{M + m + d}{3} \quad \rightarrow (1)


From the first condition:

⇒\Rightarrow Max(a,b,c) +(a, b, c) \ + Min(a,b,c)=15(a, b, c) = 15

⇒M+m=15→(2)\Rightarrow M + m = 15 \quad \rightarrow (2)


From the second condition:

⇒\Rightarrow Median(a,b,c) −(a, b, c) \ - Mean(a,b,c)=2(a, b, c) = 2

⇒d−Mean=2→(3)\Rightarrow d - \text{Mean} = 2 \quad \rightarrow (3)


Putting (1)(1) into (3)(3):

⇒d−(M+m+d3)=2\Rightarrow d - \left(\dfrac{M + m + d}{3}\right) = 2

Putting (2)(2) in the above:

⇒d−(15+d3)=2\Rightarrow d - \left(\dfrac{15 + d}{3}\right) = 2

⇒3d−15−d=6\Rightarrow 3d - 15 - d = 6

⇒2d−15=6\Rightarrow 2d - 15 = 6

⇒d=212=10.5\Rightarrow d = \dfrac{21}{2} = 10.5

Therefore, the median of aa, bb, and cc is 10.510.5.

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