Q1:

IPMAT Indore 2026

Polynomials

Easy

The equation 2x−x2=02^x - x^2 = 0 has

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2026 MCQ question 1

Q2:

IPMAT Indore 2026

Polynomials

Hard

The number of values aa can take such that x4+ax3+(3a−4)x2+2(a−1)x−4x^4 + ax^3 + (3a - 4)x^2 + 2(a - 1)x - 4 can be expressed as a product of two quadratic polynomials, x2+px+2x^2 + px + 2 and x2+qx−2x^2 + qx - 2, where pp and qq are real, is

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2026 MCQ question 2

Q3:

IPMAT Indore 2026

Polynomials

Medium

If x,yx, y are real numbers and equations x2−12x+35=0x^2 - 12x + 35 = 0 and x2+ax+105=0x^2 + ax + 105 = 0 have at least one common root, then the minimum possible value of y2+4y−5ay^2 + 4y - 5a is ___

Q4:

IPMAT Indore 2025

Polynomials

Medium

If a1,a2,...,a8a_1, a_2, ..., a_8 are the roots of the equation x8+x7+...+x+1=0x^8 + x^7 + ... + x + 1 = 0, then the value of a12025+a22025+...+a82025a_1^{2025} + a_2^{2025} + ... + a_8^{2025} is

Answer options
Option 3
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 4

Q5:

IPMAT Indore 2025

Polynomials

Medium

If 8x2−2kx+k=08x^2 - 2kx + k = 0 is a quadratic equation in xx, such that one of its roots is pp times the other, and p,kp, k are positive real numbers, then kk equals

Answer options
Option 3
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 5

Q6:

IPMAT Indore 2025

Polynomials

Hard

Let P(x)P(x) be a quadratic polynomial such that

∣P(0)P(1)P(0)P(2)∣=0\left|\begin{array}{ll} P(0) & P(1) \\ P(0) & P(2) \end{array}\right|=0

Let P(0)=2P(0)=2 and P(1)+P(2)+P(3)=14P(1)+P(2)+P(3)=14. Then P(4)P(4) equals

Answer options
Option 3
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 6

Q7:

IPMAT Indore 2025

Polynomials

Easy

Let f(x)=a2x2+2bx+cf(x) = a^2x^2 + 2bx + c where, a≠0a \neq 0, b,cb, c are real numbers and xx is a real variable then

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 7

Q8:

IPMAT Indore 2024

Polynomials

Medium

The number of real solutions of the equation (x2−15x+55)x2−5x+6=1(x^2 - 15x + 55)^{x^2-5x+6} = 1 is:

Q9:

IPMAT Indore 2024

Polynomials

Medium

The difference between the maximum real root and the minimum real root of the equation (x2−5)4+(x2−7)4=16(x^2 - 5)^4 + (x^2 - 7)^4 = 16 is

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2024 MCQ question 9

Q10:

IPMAT Indore 2023

Polynomials

Medium

If the harmonic mean of the roots of the equation (5+2)x2−bx+8+25=0(5 + \sqrt{2}) x ^ 2 - bx + 8 + 2\sqrt{5} = 0 is 44 then the value of bb is

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2023 MCQ question 10