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Q1:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Common

The matrix XX in the equation AX=BAX = B, such that A=[1302]A = \begin{bmatrix} 1 & 3 \\ 0 & 2 \end{bmatrix} and B=[1−102]B = \begin{bmatrix} 1 & -1 \\ 0 & 2 \end{bmatrix} is given by

Answer options
Option 1
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 1

Q2:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Common

Let A be any skew- symmetric matrix (where ATA^T is Transpose of matrix A). Then which of the following statements are correct?

(A) A2A^2 is a symmetric matrix

(B) A2A^2 is a skew- symmetric matrix

(C) ATA=−A2A^T A = -A^2

(D) ATA−AAT=OA^T A - AA^T = O

Choose the correct answer from the options given below:

Answer options
Option 2
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 2

Q3:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Core

If [x−y0x+y1]\begin{bmatrix} x-y & 0 \\ x+y & 1 \end{bmatrix} is an identity matrix and [xyzx]\begin{bmatrix} x & y \\ z & x \end{bmatrix} is a singular matrix then:

Answer options
Option 1
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 3

Q4:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Core

If the area of a triangle with vertices (−3,0)(-3,0), (3,0)(3, 0) and (0,k)(0, k) is 9 sq. units, then k equals

Answer options
Option 3
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 4

Q5:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Core

If x,yx, y and zz are non-zero distinct numbers, then ∣x+yy+zz+xzxy111∣\begin{vmatrix} x+y & y+z & z+x \\ z & x & y \\ 1 & 1 & 1 \end{vmatrix} is equal to

Answer options
Option 4
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 5

Q6:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Core

The system of linear equations kx+5y=5kx + 5y = 5, 2x+3y=52x + 3y = 5 will be consistent if

Answer options
Option 3
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 6

Q7:

2025: 21 May Shift 2

Matrices & Determinants

Hard

Core

If ∣1cos⁡θ0sin⁡θ1cos⁡θ∣cos⁡θ1−sin⁡θ∣∣=Asin⁡θ+Bcos⁡θ+Csin⁡θcos⁡θ\begin{vmatrix} 1 & \cos \theta & 0 \\ \sin \theta & 1 & \cos \theta \\ |\cos \theta & 1 & -\sin \theta| \end{vmatrix} = A\sin \theta + B\cos \theta + C\sin \theta\cos \theta then:

Answer options
Option 4
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 7

Q8:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Core

If A=[432−110]A = \begin{bmatrix} 4 & 3 \\ 2 & -1 \\ 1 & 0 \end{bmatrix} and BT=[12321−1]B^T = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 1 & -1 \end{bmatrix}, then A−BA - B is equal to

Answer options
Option 3
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 8

Q10:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Applied

Match List-I with List-II

List-I (Matrix A)List-II (Determinant of Adjoint of A)
(A) [3142]\begin{bmatrix} 3 & 1 \\ 4 & 2 \end{bmatrix}(I) 9
(B) [5−142]\begin{bmatrix} 5 & -1 \\ 4 & 2 \end{bmatrix}(II) 8
(C) [6−121]\begin{bmatrix} 6 & -1 \\ 2 & 1 \end{bmatrix}(III) 14
(D) [4133]\begin{bmatrix} 4 & 1 \\ 3 & 3 \end{bmatrix}(IV) 2

Choose the correct answer from the options given below:

Answer options

Q11:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Applied

If AA and BB are square matrices of the same order, then which of the following statements are correct?

(A) ∣A−1∣=∣A∣−1|A^{-1}| = |A|^{-1}

(B) adj(A)=∣A∣A−1adj(A) = |A|A^{-1}

(C) (A+B)−1=B−1+A−1(A + B)^{-1} = B^{-1} + A^{-1}

(D) (AB)−1=B−1A−1(AB)^{-1} = B^{-1}A^{-1}

Choose the correct answer from the options given below:

Answer options

Q12:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Applied

If A and B are two non-singular matrices of order n, then which of the following statement/statements is/are not correct?

(A) AB is non-singular.

(B) AB is singular.

(C) (AB)−1=A−1B−1(AB)^{-1} = A^{-1}B^{-1}

(D) (AB)−1(AB)^{-1} does not exist.

Choose the correct answer from the options given below:

Answer options

Q13:

2025: 21 May Shift 2

Matrices & Determinants

Medium

Applied

If the matrix A=[αβγ0023−20]A = \begin{bmatrix} \alpha & \beta & \gamma \\ 0 & 0 & 2 \\ 3 & -2 & 0 \end{bmatrix} is a skew symmetric matrix, then the value of (α+β+γ)2(\alpha + \beta + \gamma)^2 is:

Answer options

Q14:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Common

If A=[3−24−2]A = \begin{bmatrix} 3 & -2 \\ 4 & -2 \end{bmatrix}, I=[1001]I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} and A2=KA−2IA² = KA - 2I, then the value of K is

Answer options

Q15:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Common

Let A=[aij]3×2A = [a_{ij}]_{3×2} and B=[bij]3×4B = [b_{ij}]_{3×4} be two matrices. Then the order of the matrix (AT.B)T(A^T . B)^T is:

Answer options

Q16:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Common

Let MijM_{ij} and AijA_{ij} denote respectively minors and co-factors of the element in the ithi^{th} row and jthj^{th} column of the matrix A=[12−13234−10]A = \begin{bmatrix} 1 & 2 & -1 \\ 3 & 2 & 3 \\ 4 & -1 & 0 \end{bmatrix}. Then:

(A) M32=6M_{32} = 6

(B) M23=9M_{23} = 9

(C) A32=−6A_{32} = -6

(D) A23=−9A_{23} = -9

Choose the correct answer from the options given below:

Answer options

Q17:

2025: 21 May Shift 1

Matrices & Determinants

Easy

Common

The inverse of the matrix A=[120001400018]A = \begin{bmatrix} \frac{1}{2} & 0 & 0 \\ 0 & \frac{1}{4} & 0 \\ 0 & 0 & \frac{1}{8} \end{bmatrix} is

Answer options

Q18:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Core

If ∣1+a1111+b1111+c∣\begin{vmatrix} 1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c \end{vmatrix}, where a, b and c are non zero constants, then the value of 1a+1b+1c\frac{1}{a} + \frac{1}{b} + \frac{1}{c} is

Answer options

Q19:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Core

If the matrix A=[1321]A = \begin{bmatrix} 1 & 3 \\ 2 & 1 \end{bmatrix}, then the value of det (A2−2A)(A^2 - 2A) is equal to

Answer options

Q20:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Core

Let A be any square matrix of order n, then which of the following are true?

(A) ∣adj A∣=∣A∣n−1| \text{adj } A| = |A|^{n-1}

(B) ∣A−1∣=1∣A∣|A^{-1}| = \frac{1}{|A|}

(C) ∣adj A∣=∣A∣n| \text{adj } A| = |A|^n

(D) (AT)−1=(A−1)T(A^T)^{-1} = (A^{-1})^T

Choose the correct answer from the options given below:

Answer options

Q21:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Core

Let the matrix A=[2314]A = \begin{bmatrix} 2 & 3 \\ 1 & 4 \end{bmatrix}. Then which of the following are true?

(A) adj A=[4−3−12]A = \begin{bmatrix} 4 & -3 \\ -1 & 2 \end{bmatrix}

(B) det (A)=5(A) = 5

(C) det (adjA) = 25

(D) If A3=[abcd]A^3 = \begin{bmatrix} a & b \\ c & d \end{bmatrix}, then a+b=c+da + b = c + d

Choose the correct answer from the options given below:

Answer options

Q22:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Core

For some constant 'k', if the system of linear equations

2x−y+3z=12x - y + 3z = 1

x−2y+z=3x - 2y + z = 3

kx+y−z=0kx + y - z = 0

has a unique solution, then

Answer options

Q23:

2025: 21 May Shift 1

Matrices & Determinants

Easy

Core

If [x+y41+zy]=[2456]\begin{bmatrix} x+y & 4 \\ 1+z & y \end{bmatrix} = \begin{bmatrix} 2 & 4 \\ 5 & 6 \end{bmatrix}, then

Answer options

Q24:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Applied

The system of equations

x+ky=0x + ky = 0

3x+5y=03x + 5y = 0

has infinitely many solutions, then k is equal to

Answer options

Q25:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Applied

If A is a square matrix of order 3 such that A(adjA)=[−2000−2000−2]A( {adj } A) = \begin{bmatrix} -2 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & -2 \end{bmatrix}, then ∣A∣|A| is equal to

Answer options

Q26:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Applied

If [1391xx2469]\begin{bmatrix} 1 & 3 & 9 \\ 1 & x & x^2 \\ 4 & 6 & 9 \end{bmatrix} is singular matrix, where x∈Nx \in \mathbb{N} (where N set of natural number), then x is equal to

Answer options

Q27:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Applied

If [x−yt2x−yw]=[−1201]\begin{bmatrix} x-y & t \\ 2x-y & w \end{bmatrix} = \begin{bmatrix} -1 & 2 \\ 0 & 1 \end{bmatrix}, then 2x+y+3t+w2x + y + 3t + w is equal to

Answer options

Q28:

2025: 21 May Shift 1

Matrices & Determinants

Medium

Applied

If A and B are symmetric matrices of same order, then which of the following are correct?

(A) AB-BA is a skew-symmetric matrix.

(B) AB+BA is a skew-symmetric matrix.

(C) ABT−BATAB^T-BA^T is a skew-symmetric matrix.

(D) AB+BA is a symmetric matrix.

Choose the correct answer from the options given below:

Answer options

Q29:

2025: 19 May Shift 1

Matrices & Determinants

Medium

Common

If A=[1101]A = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix}, then the value of A20A^{20} is:

Answer options

Q30:

2025: 19 May Shift 1

Matrices & Determinants

Medium

Common

If A=[2134−35]A = \begin{bmatrix} 2 & 1 & 3 \\ 4 & -3 & 5 \end{bmatrix} and B=[−234−512]B = \begin{bmatrix} -2 & 3 \\ 4 & -5 \\ 1 & 2 \end{bmatrix}, then which of the following statements are TRUE?

(A) AB is defined

(B) AB and BA both are defined and AB = I, where I is an identity matrix of order 2

(C) BA is defined

(D) AB and BA both are defined and AB = BA

Choose the correct answer from the options given below:

Answer options