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The probability distribution of a discrete random variable X is given by :

X3010-10
P(X)1/53/101/2

then E(X) is equals to

Solution

✅ Correct Option: 2

E(X)=30×15+10×310+(−10)×12=6+3−5=4E(X) = 30 \times \frac{1}{5} + 10 \times \frac{3}{10} + (-10) \times \frac{1}{2} = 6 + 3 - 5 = 4.

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