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The interval in which where the function f(x)=x3−3x2+4x+1,x∈Rf(x) = x^3 - 3x^2 + 4x + 1, x \in R is increasing in, is :

Solution

✅ Correct Option: 4

f′(x)=3x2−6x+4=3(x−1)2+1f'(x) = 3x^2 - 6x + 4 = 3(x-1)^2 + 1, which is always positive. So ff is increasing on the entire real line RR.

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