The interval in which where the function f(x) = x^3 - 3x^2 + 4x + 1, x R is increasing in, is : Option 1: [2,3] Option 2: [-2,4] Option 3: [0,2] Option 4: R

The answer is 'R'. View full solution:

CUET Mathematics - The interval in which where the function f(x) = x^3 - 3x^2 + 4x + 1, x R is increasing in, is : | PYQs + Solutions

CUET Mathematics 2023 11 Aug Shift 1

Applied Mathematics

Easy

[2,3]

[-2,4]

[0,2]

✅ Correct Option: 4

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The minimum value of $f(x) = 4x^3 - 48x + 105$ in the interval [1,3] is :

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The value of a for which the function $f(x) = a^x$ is increasing on R are given by :

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Match List - I with List - II.

List - I	List - II
(A) The minimum value of $f(x) = 8x^2 - 4x + 7$ is	(I) 48
(B) The maximum value of $f(x) = x + \frac{1}{x}$ , $x < 0$ is	(II) 13
(C) The maximum slope of the curve $y = -2x^3 + 6x^2 + 7x + 26$ is	(III) $-2$
(D) The minimum value of $f(x) = x^2 + \frac{128}{x}$ is	(IV) $\frac{13}{2}$

Choose the correct answer from the options given below :