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If P=[−220314]P = \begin{bmatrix} -2 & 2 & 0 \\ 3 & 1 & 4 \end{bmatrix} and Q=[20−2716]Q = \begin{bmatrix} 2 & 0 & -2 \\ 7 & 1 & 6 \end{bmatrix}, If 5Q−3P+2R=05Q - 3P + 2R = 0, then the matrix R is

Solution

✅ Correct Option: 3

2R=3P−5Q2R = 3P - 5Q. 3P=[−6609312]3P = \begin{bmatrix} -6 & 6 & 0 \\ 9 & 3 & 12 \end{bmatrix}, 5Q=[100−1035530]5Q = \begin{bmatrix} 10 & 0 & -10 \\ 35 & 5 & 30 \end{bmatrix}. 3P−5Q=[−16610−26−2−18]3P - 5Q = \begin{bmatrix} -16 & 6 & 10 \\ -26 & -2 & -18 \end{bmatrix}. Dividing by 2: R=[−835−13−1−9]R = \begin{bmatrix} -8 & 3 & 5 \\ -13 & -1 & -9 \end{bmatrix}.

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