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If A=[10−17],I=[1001]A = \begin{bmatrix} 1 & 0 \\ -1 & 7 \end{bmatrix}, I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} and A2=8A+kIA^2 = 8A + kI, the value of k is :

Solution

✅ Correct Option: 2

A2=[10−849]A^2 = \begin{bmatrix} 1 & 0 \\ -8 & 49 \end{bmatrix} and 8A+kI=[8+k0−856+k]8A + kI = \begin{bmatrix} 8+k & 0 \\ -8 & 56+k \end{bmatrix}. Equating, 1=8+k1 = 8 + k gives k=−7k = -7, consistent with 49=56+k49 = 56 + k.

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