The least positive integer X satisfying 28 x ( 6) is : Option 1: 24 Option 2: 4 Option 3: 5 Option 4: 2

Answer: 4. Solution: 28 = 6 x 4 + 4, so 28 6 = 4. The least positive integer x satisfying 28 x ±od6 is x = 4.

Applied Mathematics

Algebra

Easy

The least positive integer X satisfying $28 \equiv x (\mod 6)$ is :

✅ Correct Option: 2

$28 = 6 \times 4 + 4$ , so $28 \bmod 6 = 4$ . The least positive integer $x$ satisfying $28 \equiv x \pmod{6}$ is $x = 4$ .

2026: 14 May Shift 2

Match the LIST-I with LIST-II

	LIST-I		LIST-II
A.	A matrix which is both symmetric and skew symmetric	I.	symmetric matrix
B.	All positive integral powers of a symmetric matrix	II.	unit matrix
C.	Positive odd integral powers of a skew-symmetric matrix	III.	null matrix
D.	A square matrix $A = [a_{ij}]_{n\times n}$ with $a_{ij} = \begin{cases}0, & \forall\, i \neq j \\ 1, & \forall\, i = j\end{cases}$	IV.	skew-symmetric matrix

Choose the correct answer from the options given below:

2023: 7 June Shift 1

A matrix has 24 elements , which of the following cannot be the possible order of the matrix

2023: 22 May Shift 3

Match List - I with List - II.

Choose the correct answer from the options given below :

2023: 11 Aug Shift 1

If $\begin{vmatrix} -a^2 & ab & ac \\ ba & -b^2 & bc \\ ac & bc & -c^2 \end{vmatrix} = 4x$ , then $x =$

2023: 22 May Shift 3

If $K \equiv 5 \pmod{11}$ , then all the possible non-negative values of K are :

2023: 7 June Shift 1

Matrix $A = \begin{bmatrix} 0 & a & 5 \\ 4 & b & -1 \\ c & 1 & 0 \end{bmatrix}$ is skew - symmetric, then the values of a, b c are :