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Match list I with list II

List - IList - II
A. Slope of tangent to the curve y=x3−xy = x^3 - x at x=2x = 2I. −2-2
B. Slope of tangent to the curve y=3x3−4xy = 3x^3 - 4x at x=0x = 0II. 1111
C. Slope of normal to the curve y=sin⁡θy = \sin\theta at θ=π3\theta = \frac{\pi}{3}III. 22
D. Slope of normal to the curve y=cos⁡θy = \cos\theta at θ=π6\theta = \frac{\pi}{6}IV. −4-4

Choose the correct answer from the option given below :

Solution

✅ Correct Option: 1

A: y′=3x2−1y' = 3x^2 - 1, at x=2x=2: 1111 (II). B: y′=9x2−4y' = 9x^2 - 4, at x=0x=0: −4-4 (IV). C: tangent slope =cos⁡(π/3)=1/2= \cos(\pi/3) = 1/2, normal slope =−2= -2 (I). D: tangent slope =−sin⁡(π/6)=−1/2= -\sin(\pi/6) = -1/2, normal slope =2= 2 (III). Match: A-II, B-IV, C-I, D-III.

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