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If A and B are square matrices of same order, then A′B−B′AA'B - B'A is a:

Solution

✅ Correct Option: 1

Let P=A′B−B′AP = A'B - B'A. Then P′=(A′B)′−(B′A)′=B′A−A′B=−(A′B−B′A)=−PP' = (A'B)' - (B'A)' = B'A - A'B = -(A'B - B'A) = -P. Since P′=−PP' = -P, the matrix is skew symmetric.

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