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Let R:R→RR : \mathbb{R} \to \mathbb{R}, where R\mathbb{R} is the set of real numbers and R be a relation. An element (x,y)∈R(x, y) \in R if x+y−2x + y - \sqrt{2} belongs to the set of irrational numbers. Then the relation R is :

Solution

✅ Correct Option: 2

Symmetric: if x+y−2x+y-\sqrt{2} is irrational, then y+x−2y+x-\sqrt{2} is the same expression, so symmetric holds. Reflexive needs 2x−22x-\sqrt{2} irrational for all xx, fails for x=2/2x=\sqrt{2}/2. Transitive fails too. So only symmetric.

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