Two cards are drawn successively with replacement from a well shuffled deck of 52 cards. The probability distribution of the number of kings will be: Option 1: | x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 1/169 | 24/169 | 144/169 | Option 2: | x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 24/169 | 144/169 | 1/169 | Option 3: | x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 1/169 | 24/169 | 144/169 | Option 4: | x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 144/169 | 24/169 | 1/169 |

The answer is '| x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 144/169 | 24/169 | 1/169 |'. View full solution:

Two cards are drawn successively with replacement from a well shuff<=d deck of 52 cards. The probability distribution of the number of kings will be:

| x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 144/169 | 24/169 | 1/169 |

| x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 1/169 | 24/169 | 144/169 |

| x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 24/169 | 144/169 | 1/169 |

| x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 1/169 | 24/169 | 144/169 |

| x | 0 | 1 | 2 | |---|---|---|---| | P(X=x) | 144/169 | 24/169 | 1/169 |

CUET Mathematics 2022 4 Aug Shift 1

Algebra

Easy

x	0	1	2
P(X=x)	$\frac{1}{169}$	$\frac{24}{169}$	$\frac{144}{169}$

x	0	1	2
P(X=x)	$\frac{24}{169}$	$\frac{144}{169}$	$\frac{1}{169}$

x	0	1	2
P(X=x)	$\frac{1}{169}$	$\frac{24}{169}$	$\frac{144}{169}$

x	0	1	2
P(X=x)	$\frac{144}{169}$	$\frac{24}{169}$	$\frac{1}{169}$

✅ Correct Option: 4