In a class of 30 students, 10 scored 40, 12 scored 50, 8 scored 60. The mean score is: Option 1: 49.33 Option 2: 47.30 Option 3: 52.32 Option 4: 45

Answer: 49.33. Solution: Total marks = 10(40) + 12(50) + 8(60) = 400 + 600 + 480 = 1480. Mean = 1480/30 = 49.33.

Arithmetic

Central Tendency

Easy

In a class of 30 students, 10 scored 40, 12 scored 50, 8 scored 60. The mean score is:

49.33

47.30

52.32

✅ Correct Option: 1

Total marks $= 10(40) + 12(50) + 8(60) = 400 + 600 + 480 = 1480$ .

Mean $= \frac{1480}{30} = 49.33$ .

2025: 13 May Shift 2

The median of the observations: 12, 59, 14, 46, 18, 42, 26, 33, 22 is:

2025: 3 June Shift 1

Consider the following frequency distribution.

Class	0-10	10-20	20-30	30-40	40-50	50-60	60-70
Frequency	4	5	7	10	12	8	4

Find the median of the distribution?

2022: 17 Aug Shift 1

The mode of data in numerals is

2022: 6 Aug Shift 1

Median of the data is:

2025: 16 May Shift 1

Find the median of the following observations.

6, 49, 14, 46, 16, 42, 26, 32, 28

2025: 30 May Shift 2

Match List I with List II

List I	List II
Statistical Measure	Definition
(A) Mode	(I) Sum of all observations divided by their count
(B) Median	(II) Measure of the spread from the mean
(C) Mean	(III) Central value when observations are arranged in order
(D) Standard Deviation	(IV) Observation which has the highest frequency

Choose the correct answer from the options given below: