Arithmetic

Central Tendency

Easy

For a certain distribution, mode and median were found to be 1000 and 1250 respectively. Find the mean of this distribution using an empirical relation.

1175

1375

1050

975

✅ Correct Option: 2

Empirical relation: Mode $= 3\,$ Median $- 2\,$ Mean. So $1000 = 3(1250) - 2\text{Mean}$ , giving $2\text{Mean} = 3750 - 1000 = 2750$ and Mean $= 1375$ .

2025: 3 June Shift 1

Consider the following frequency distribution.

Class	0-10	10-20	20-30	30-40	40-50	50-60	60-70
Frequency	4	5	7	10	12	8	4

Find the median of the distribution?

2026: 18 May Shift 2

The mean of 5 numbers is 15. If one more number is included, the mean of the 6 numbers becomes 17. Find the included number.

2025: 26 May Shift 1

The Mean and Median of 7 observations are 10 and 9, respectively. If 2 is subtracted from each observation, then the new Median and the new Mean will be:

2026: 12 May Shift 2

The mean of 50 observations was 46. Upon checking, it was found that two observations were wrongly copied as 5 and 8. If incorrect observations are replaced by the corrected values 12 and 14, then find the corrected mean.

2025: 28 May Shift 2

In the first 9 matches of a cricket tournament, the wickets taken by Jumpo are as follows:

3 2 0 1 3 0 5 1 4

Find the median of the number of wickets taken by Jumpo?

2025: 29 May Shift 1

The median and mean of 7 observations are 9 and 11 respectively. If 2 is subtracted from each observation, then the new median and the new mean will respectively be which of the following?

For a certain distribution, mode and median were found to be 1000 and 1250 respectively. Find the mean of this distribution using an empirical relation.

Solution

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