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The mean of 30 observations was 15. Upon checking, it was found that two observations were wrongly taken as 2 and 5. If incorrect observations are replaced by the corrected values 7 and 11, then the corrected mean is?

Solution

✅ Correct Option: 1

Original sum =30×15=450= 30 \times 15 = 450. Corrected sum =450−(2+5)+(7+11)=450−7+18=461= 450 - (2+5) + (7+11) = 450 - 7 + 18 = 461. Corrected mean =46130=15.36= \frac{461}{30} = 15.36 approximately.

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