Arithmetic

Central Tendency

Medium

The following are the marks obtained in a class test by a student: 10, 12, 15, 15, 18, 20, 20, 20, 23. The variance is?

15.2

15.4

16.2

16.4

✅ Correct Option: 3

Sum $= 153$ , $n = 9$ , so mean $= 17$ .

Deviations: $-7, -5, -2, -2, 1, 3, 3, 3, 6$ .

Sum of squares $= 49 + 25 + 4 + 4 + 1 + 9 + 9 + 9 + 36 = 146$ .

Variance $= \frac{146}{9} \approx 16.2$ .

2022: 8 Aug Shift 1

Find the mean of 12, 15, 7, 8 and 'x + 13', if x = 2

2025: 29 May Shift 2

The median of a set of 11 distinct observations is 22.5. If each of the largest 5 observations of the set is increased by 5, then the median of the new set

2026: 29 May Shift 2

Salma bought 65 books for ₹ 1050 from one shop and 50 books for ₹ 1020 from another. What is the mean price she paid per book?

2026: 21 May Shift 1

Find the mean deviation about the median for the following data set:

3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21.

2022: 6 Aug Shift 1

Mean of the data is:

2022: 6 Aug Shift 1

The mode of the data is:

The following are the marks obtained in a class test by a student: 10, 12, 15, 15, 18, 20, 20, 20, 23. The variance is?

Solution

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