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The mean of 50 observations was 46. Upon checking, it was found that two observations were wrongly copied as 5 and 8. If incorrect observations are replaced by the corrected values 12 and 14, then find the corrected mean.

Solution

✅ Correct Option: 3

Original sum =50×46=2300=50\times46=2300.

Correction =(12+14)−(5+8)=26−13=13=(12+14)-(5+8)=26-13=13.

Corrected sum =2313=2313, so corrected mean =231350=46.26=\frac{2313}{50}=46.26.

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