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Dittee has 10 purses and each of which having an average of 25 lipsticks in each purse. Further, it is known that each purse has a minimum of 8 lipsticks and none of the purse has identical number of lipsticks.

Determine that what can be the maximum number of lipsticks that Dittee shall have in any of her purse?

Solution

✅ Correct Option: 1

Total number of purses = 10

Average lipsticks per purse = 25

Total lipsticks = 10×25=25010 \times 25 = 250


To maximize the number of lipsticks in one purse, we minimize the number in the other 9 purses.

Given constraints:

  • Each purse must have at least 8 lipsticks
  • No two purses can have the same number of lipsticks

The minimum possible values for 9 purses are: 8, 9, 10, 11, 12, 13, 14, 15, 16


Sum of lipsticks in these 9 purses:

8+9+10+11+12+13+14+15+168 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16

=(8+16)+(9+15)+(10+14)+(11+13)+12= (8 + 16) + (9 + 15) + (10 + 14) + (11 + 13) + 12

=24+24+24+24+12= 24 + 24 + 24 + 24 + 12

=108= 108


Maximum lipsticks in the 10th purse:

=250−108= 250 - 108

=142= 142

Therefore, the maximum number of lipsticks in any purse is 142.

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