Arithmetic

Central Tendency

Medium

The median of frequency distribution is:

Class : 0 – 25 25 – 50 50 – 75 75 – 100
Frequency : 23 32 15 12

Class :	0 – 25	25 – 50	50 – 75	75 – 100
Frequency :	23	32	15	12

39.06

32.09

33.07

38.12

✅ Correct Option: 1

Total frequency $N = 82$ , so $N/2 = 41$ . Cumulative frequencies are 23, 55, 70, 82, so the median class is 25-50 with $l = 25$ , $cf = 23$ , $f = 32$ , $h = 25$ . Median $= 25 + \frac{41-23}{32} \times 25 = 25 + 14.06 = 39.06$ .

2025: 22 May Shift 2

2, 4, 5, 2, 4, 8, 2, 4, 7, 8, 12, 4,

The mode of given data is:

2026: 14 May Shift 1

The relation between Mean, Median and Mode is:

2026: 25 May Shift 2

The median of numbers 14, 7, 18, 21 and 27 is:

2025: 13 May Shift 1

The marks out of 50 obtained by 100 students in a test are given below as:

Marks obtained	20	25	28	29	33	38	42	43
Number of students	6	20	24	28	15	4	2	1

Find the value of the (3 mode - 2 median).

2022: 23 Aug Shift 1

The average of first 99 positive integers is:

2025: 26 May Shift 1

The Mean and Median of 7 observations are 10 and 9, respectively. If 2 is subtracted from each observation, then the new Median and the new Mean will be:

The median of frequency distribution is: Class :0 – 2525 – 5050 – 7575 – 100Frequency :23321512

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)

The median of frequency distribution is:

Class : 0 – 25 25 – 50 50 – 75 75 – 100
Frequency : 23 32 15 12