Arithmetic

Central Tendency

Hard

The median of the following frequency distribution is 52. If the total frequency is 50, the values of x and y are:

Class Interval Class Frequency
0-10 1
10-20 3
20-30 x
30-40 6
40-50 5
50-60 8
60-70 y
70-80 7
80-90 5
90-100 3

Class Interval	Class Frequency
0-10	1
10-20	3
20-30	x
30-40	6
40-50	5
50-60	8
60-70	y
70-80	7
80-90	5
90-100	3

x=6, y=6

x=7, y=5

x=5, y=7

x=9, y=3

✅ Drop

Known frequencies sum to 38, so $x + y = 12$ .

Since the median 52 lies in 50-60, use

$\text{Median} = L + \frac{N/2 - cf}{f} \times h$

with $L=50$ , $N/2=25$ , $cf=15+x$ , $f=8$ , and $h=10$ .

So,

$52 = 50 + \frac{10-x}{8}\times 10$

which gives $x=8.4$ .

Since frequency cannot be 8.4 and none of the options work, the question is inconsistent.

NTA eventually dropped the question. Fair enough. Your crush probably did the same.

2026: 19 May Shift 2

The following table shows the ages of the patients admitted in a hospital during a year:

Age (in year)	5-15	15-25	25-35	35-45	45-55	55-65
Number of patients	6	11	19	23	14	7

Find the mean of the above data.

2025: 21 May Shift 1

The mean of 6 numbers is 19. If two more numbers are included, the mean of the 8 numbers becomes 23. What is the sum of the two included numbers?

2025: 22 May Shift 2

2, 4, 5, 2, 4, 8, 2, 4, 7, 8, 12, 4,

The mode of given data is:

2025: 15 May Shift 1

Read the information given below carefully and answer the question that follows:

(A) If the mean of 5 numbers is 15 and then if 27 is included to the numbers, then the mean of the 6 numbers shall be 17

(B) The mean of marks of 300 students is 60, the mean of the top 100 students' marks is 80 and the mean of the last 100 students is 50, then the mean of the marks of the rest of the 100 students of the group is 60.

(C) The mean and median of 5 observations is 9 and 8 respectively, if 1 is subtracted from each observation, then the new mean and median shall be 8 and 7 respectively

Choose the correct answer from the options given below:

2023: 21 May Shift 1

The average of 12 numbers is 15 and the average of the first two numbers is 14. What is the average of the remaining numbers?

2023: 28 May Shift 1

Thirty six students of class IX contributed on an average Rs 42 towards flood relief fund whereas some students of class X contributed on an average Rs 54.50. If the overall average contribution per student remained Rs 47, then how many students of class X contributed ?

The median of the following frequency distribution is 52. If the total frequency is 50, the values of x and y are: Class IntervalClass Frequency0-10110-20320-30x30-40640-50550-60860-70y70-80780-90590-1003

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)

The median of the following frequency distribution is 52. If the total frequency is 50, the values of x and y are:

Class Interval Class Frequency
0-10 1
10-20 3
20-30 x
30-40 6
40-50 5
50-60 8
60-70 y
70-80 7
80-90 5
90-100 3