Arithmetic

Central Tendency

Medium

The A.M.(Arithmetic Mean) and G.M (Geometric Mean) of two positive numbers p and q are 8 and 4 respectively, then the value of p - q are

$\sqrt{192}$

192

✅ Correct Option: 3

AM $= 8$ gives $p + q = 16$ ; GM $= 4$ gives $pq = 16$ . Then $(p - q)^2 = (p + q)^2 - 4pq = 256 - 64 = 192$ , so $p - q = \sqrt{192}$ .

2026: 25 May Shift 2

The mean of 40 observations was 34. Upon checking, it was found that two observations were wrongly copied as 4 and 7. If incorrect observations are replaced by the corrected values 11 and 13, then find the corrected mean.

2025: 21 May Shift 1

The mean of 6 numbers is 19. If two more numbers are included, the mean of the 8 numbers becomes 23. What is the sum of the two included numbers?

2025: 13 May Shift 1

The marks out of 50 obtained by 100 students in a test are given below as:

Marks obtained	20	25	28	29	33	38	42	43
Number of students	6	20	24	28	15	4	2	1

Find the value of the (3 mode - 2 median).

2026: 18 May Shift 2

The mean of 5 numbers is 15. If one more number is included, the mean of the 6 numbers becomes 17. Find the included number.

2024

In a class of 40 students, ratio of boys and girls is 3:2 and the average marks scored by boys is 42 and that by girls is 46. Then the average marks scored by the whole class is :

2025: 14 May Shift 2

Find out the median of the following frequency distribution:

Variable	11	12	13	14	15	16	17	18	Total
Frequency	5	7	11	9	8	7	3	5	55

The A.M.(Arithmetic Mean) and G.M (Geometric Mean) of two positive numbers p and q are 8 and 4 respectively, then the value of p - q are

Solution

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