If numerator of fraction is increased by 150% and denominator is increased by 50% the resultant fraction becomes 15/16. What was the original fraction? Option 1: 3/16 Option 2: 1/16 Option 3: 7/16 Option 4: 9/16

Answer: 9/16. Solution: Let the fraction be x/y. After the increases it becomes 2.5x/1.5y = 5x/3y. Setting 5x/3y = 15/16 gives x/y = (15 x 3)/(16 x 5) = 45/80 = 9/16.

Arithmetic

Percentages

Medium

If numerator of fraction is increased by 150% and denominator is increased by 50% the resultant fraction becomes $\frac{15}{16}$ . What was the original fraction?

$\frac{3}{16}$

$\frac{1}{16}$

$\frac{7}{16}$

$\frac{9}{16}$

✅ Correct Option: 4

Let the fraction be $\dfrac{x}{y}$ . After the increases it becomes $\dfrac{2.5x}{1.5y} = \dfrac{5x}{3y}$ .

Setting $\dfrac{5x}{3y} = \dfrac{15}{16}$ gives $\dfrac{x}{y} = \dfrac{15 \times 3}{16 \times 5} = \dfrac{45}{80} = \dfrac{9}{16}$ .

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Match List-I with List-II

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Choose the correct answer from the options given below:

If numerator of fraction is increased by 150% and denominator is increased by 50% the resultant fraction becomes 1516\frac{15}{16}1615​. What was the original fraction?

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CUET General Test Past Year Questions (Topic-Wise)

If numerator of fraction is increased by 150% and denominator is increased by 50% the resultant fraction becomes $\frac{15}{16}$ . What was the original fraction?