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Two unbiased coins are tossed:

Match the List-I and List-II

List-IList-II
(A) Probability of getting one head(I) 3/4
(B) Probability of getting two heads(II) 1/2
(C) Probability of getting at most one head(III) 1/4
(D) Probability of getting three heads(IV) 0

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

The sample space is HH, HT, TH, TT.

Exactly one head: HT and TH, so 2/4=1/22/4 = 1/2, giving (A)-(II).

Two heads: only HH, so 1/41/4, giving (B)-(III).

At most one head: all outcomes except HH, so 3/43/4, giving (C)-(I).

Three heads is impossible with two coins, so probability 00, giving (D)-(IV).

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