The reflection of the point (6, - 3) on the line y = 2 is:

The line $y = 2$ is a horizontal line parallel to the x-axis. When reflecting a point across this line, the point flips to the other side at the same distance from the line.

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When reflecting across a horizontal line $y = k$, the x-coordinate remains unchanged. The point only moves vertically.

The reflected point will have $x = 6$ (same as the original).

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Original point: $(6, -3)$

Mirror line: $y = 2$

Distance $= |2 - (-3)|$

Distance $= |2 + 3|$

Distance $= 5$ units

The point $(6, -3)$ is $5$ units below the line $y = 2$ since $-3 < 2$.

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The reflected point must be $5$ units above the line $y = 2$.

New y-coordinate $= 2 + 5$

New y-coordinate $= 7$

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The reflected point is $(6, 7)$.

Alternatively, using the formula for reflection across horizontal line $y = k$:

New point $= (x, 2k - y_1)$

New point $= (6, 2(2) - (-3))$

New point $= (6, 4 + 3)$

New point $= (6, 7)$