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Solution

✅ Correct Option: 1

A number that is both a perfect square and a perfect cube must be a perfect sixth power.

64=2664 = 2^6, so 64=82=4364 = 8^2 = 4^3.

The others fail: 72=23×3272 = 2^3 \times 3^2, 128=27128 = 2^7 which is a cube-free exponent for squares, and 200=23×52200 = 2^3 \times 5^2.

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