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If the ratio of the radii of the sphere and hemisphere is √3:2, then determine the ratio of their total surface area?

Solution

✅ Correct Option: 4

The ratio of radii is Sphere : Hemisphere =3:2= \sqrt{3} : 2.

Let the radius of sphere R1=3kR_1 = \sqrt{3}k and radius of hemisphere R2=2kR_2 = 2k, where kk is a constant.


The total surface area of a sphere is 4πr24\pi r^2.

The total surface area of a hemisphere includes the curved surface and the flat circular base: 2πr2+πr2=3πr22\pi r^2 + \pi r^2 = 3\pi r^2.


Total surface area of sphere:

TSAsphere=4π(R1)2\text{TSA}_{\text{sphere}} = 4\pi(R_1)^2

=4π(3k)2= 4\pi(\sqrt{3}k)^2

=4π×3k2= 4\pi \times 3k^2

=12πk2= 12\pi k^2


Total surface area of hemisphere:

TSAhemisphere=3π(R2)2\text{TSA}_{\text{hemisphere}} = 3\pi(R_2)^2

=3π(2k)2= 3\pi(2k)^2

=3π×4k2= 3\pi \times 4k^2

=12πk2= 12\pi k^2


The ratio of total surface areas:

TSAsphere:TSAhemisphere=12πk2:12πk2\text{TSA}_{\text{sphere}} : \text{TSA}_{\text{hemisphere}} = 12\pi k^2 : 12\pi k^2

=1:1= 1 : 1

Therefore, the ratio of their total surface areas is 1:11:1.

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