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The ratio of radii of two right circular cylinders (A and B) is 2:3. The ratio of volumes of the cylinders A and B is 9:7, then what is the ratio of the heights of the cylinders A and B?

Solution

✅ Correct Option: 4

Given:

  • Ratio of radii (A : B) = 2 : 3
  • Ratio of volumes (A : B) = 9 : 7

The volume of a cylinder is πr2h\pi r^2 h


Let the radius of cylinder A be rA=2kr_A = 2k and the radius of cylinder B be rB=3kr_B = 3k


The ratio of volumes can be written as:

VAVB=97\dfrac{V_A}{V_B} = \dfrac{9}{7}

πrA2hAπrB2hB=97\dfrac{\pi r_A^2 h_A}{\pi r_B^2 h_B} = \dfrac{9}{7}

rA2hArB2hB=97\dfrac{r_A^2 h_A}{r_B^2 h_B} = \dfrac{9}{7}


Rearranging:

(rArB)2×hAhB=97\left(\dfrac{r_A}{r_B}\right)^2 \times \dfrac{h_A}{h_B} = \dfrac{9}{7}

Substituting rArB=23\dfrac{r_A}{r_B} = \dfrac{2}{3}:

(23)2×hAhB=97\left(\dfrac{2}{3}\right)^2 \times \dfrac{h_A}{h_B} = \dfrac{9}{7}

49×hAhB=97\dfrac{4}{9} \times \dfrac{h_A}{h_B} = \dfrac{9}{7}


Solving for the height ratio:

hAhB=97×94\dfrac{h_A}{h_B} = \dfrac{9}{7} \times \dfrac{9}{4}

hAhB=8128\dfrac{h_A}{h_B} = \dfrac{81}{28}

Therefore, the ratio of heights (A : B) = 81 : 28

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