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P can build a wall in the same time in which Q and R together can do it. If P and Q together could do it in 30 days and R alone in 40 days, in what time could Q alone do it?

Solution

✅ Correct Option: 1

R alone can complete the wall in 40 days.

P and Q together can complete it in 30 days.

P alone takes the same time as Q and R working together.

If someone completes a job in nn days, their work rate is 1n\frac{1}{n} of the job per day.

Q's rate =1q= \frac{1}{q} (where qq is the days Q needs)

R's rate =140= \frac{1}{40} per day

P's rate =1p= \frac{1}{p} (where pp is the days P needs)


When people work together, their rates are added.

P and Q together take 30 days:

1p+1q=130\frac{1}{p} + \frac{1}{q} = \frac{1}{30} ... (Equation 1)


P alone equals Q and R together:

1p=1q+140\frac{1}{p} = \frac{1}{q} + \frac{1}{40} ... (Equation 2)


Substituting Equation 2 into Equation 1:

(1q+140)+1q=130\left(\frac{1}{q} + \frac{1}{40}\right) + \frac{1}{q} = \frac{1}{30}

2q+140=130\frac{2}{q} + \frac{1}{40} = \frac{1}{30}

2q=130−140\frac{2}{q} = \frac{1}{30} - \frac{1}{40}


Finding common denominator (LCM of 30 and 40 is 120):

130=4120\frac{1}{30} = \frac{4}{120}

140=3120\frac{1}{40} = \frac{3}{120}

2q=4120−3120\frac{2}{q} = \frac{4}{120} - \frac{3}{120}

2q=1120\frac{2}{q} = \frac{1}{120}


2q=1120\frac{2}{q} = \frac{1}{120}

q=2×120q = 2 \times 120

q=240q = 240

Therefore, Q alone can build the wall in 240 days.

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