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A is twice as good as a workman B and together they finish a piece of work in 18 days. In how many days will A alone finish the work?

Solution

✅ Correct Option: 4

Let B's one day work be xx, so A's is 2x2x. Together 3x=1183x = \frac{1}{18}, giving x=154x = \frac{1}{54}. A's one day work is 2x=1272x = \frac{1}{27}, so A alone takes 2727 days.

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