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A and B working together can finish a piece of work in 12 days while B alone can finish the same work in 30 days. Then determine that in how many days can A alone finish the same work?

Solution

✅ Correct Option: 2

When people work together, their work speeds add up. If someone finishes work in nn days, they do 1n\frac{1}{n} work per day.


B alone finishes work in 30 days.

B's work per day =130= \frac{1}{30} of the total work


A and B together finish work in 12 days.

(A + B)'s work per day =112= \frac{1}{12} of the total work


Since A and B's speeds add up:

A's work per day =112−130= \frac{1}{12} - \frac{1}{30}

Finding common denominator (LCM of 12 and 30 is 60):

112=560\frac{1}{12} = \frac{5}{60}

130=260\frac{1}{30} = \frac{2}{60}

A's work per day =560−260= \frac{5}{60} - \frac{2}{60}

A's work per day =360= \frac{3}{60}

A's work per day =120= \frac{1}{20}


If A does 120\frac{1}{20} work per day, then A needs 20 days to complete the whole work.

Therefore, A alone can finish the work in 20 days.

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