If all the numbers from 5 to 85 which are exactly divisible by 5 are arranged in descending order, then which of the below given numbers shall come at the eleventh place from the bottom?

The numbers from 5 to 85 that are exactly divisible by 5 are:

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85

Total count: $(85 - 5) \div 5 + 1 = 17$ numbers

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Arranging in descending order:

85, 80, 75, 70, 65, 60, 55, 50, 45, 40, 35, 30, 25, 20, 15, 10, 5

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Counting from the bottom (starting from 5):

1st from bottom: 5

2nd from bottom: 10

3rd from bottom: 15

4th from bottom: 20

5th from bottom: 25

6th from bottom: 30

7th from bottom: 35

8th from bottom: 40

9th from bottom: 45

10th from bottom: 50

11th from bottom: 55

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Therefore, the number at the eleventh place from the bottom is 55.