The area of a right-angled triangle with hypotenuse 17 cm and one side being 8 cm shall be:

The hypotenuse is 17 cm and one side is 8 cm.

Using the Pythagorean Theorem:

$(Hypotenuse)^2 = (Side_1)^2 + (Side_2)^2$

$(17)^2 = (8)^2 + (Side_2)^2$

$289 = 64 + (Side_2)^2$

$(Side_2)^2 = 289 - 64$

$(Side_2)^2 = 225$

$Side_2 = \sqrt{225}$

$Side_2 = 15$ cm

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The two sides are 8 cm and 15 cm.

In a right-angled triangle, the two sides (not the hypotenuse) act as base and height.

Area $= \dfrac{1}{2} \times base \times height$

Area $= \dfrac{1}{2} \times 8 \times 15$

Area $= \dfrac{1}{2} \times 120$

Area $= 60$ cm²

Therefore, the area of the right-angled triangle is 60 cm².