Skip to main contentSkip to solution

If a certain sum becomes three times in 4 years at compound interest, then in how many years, will it become 9 times?

Solution

✅ Correct Option: 3

Let the principal amount be PP and the growth factor be (1+r)(1 + r) where rr is the rate of interest.

Using the compound interest formula:

A=P(1+r)tA = P(1 + r)^t


When the amount becomes 3 times in 4 years:

3P=P(1+r)43P = P(1 + r)^4

3=(1+r)43 = (1 + r)^4


For the amount to become 9 times after nn years:

9P=P(1+r)n9P = P(1 + r)^n

9=(1+r)n9 = (1 + r)^n


Notice that 9=329 = 3^2:

9=329 = 3^2

9=[(1+r)4]29 = [(1 + r)^4]^2

9=(1+r)4×29 = (1 + r)^{4 \times 2}

9=(1+r)89 = (1 + r)^8


Comparing 9=(1+r)n9 = (1 + r)^n with 9=(1+r)89 = (1 + r)^8:

n=8n = 8

Therefore, the amount will become 9 times in 8 years.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question