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In a square, lengths of the diagonals are (4k+6)(4k + 6) cm and (7k3)(7k − 3) cm. The area of the square (in cm²) is:

Solution

Correct Option: 2

Since the diagonals of a square are equal, we can set the two expressions for the diagonals equal to each other:

4k+6=7k34k + 6 = 7k - 3

Now, solve for kk:

6+3=7k4k6 + 3 = 7k - 4k

9=3k9 = 3k

k=3k = 3

Now, substitute kk back into one of the diagonal expressions to find the length of the diagonal:

Diagonal = 4(3)+6=12+6=184(3) + 6 = 12 + 6 = 18 cm.

The area of the square can be calculated using the formula for the area in terms of the diagonal:

Area = d22\frac{d^2}{2}, where dd is the length of the diagonal.

Area = 1822=3242=162\frac{18^2}{2} = \frac{324}{2} = 162 cm².

Thus, the area of the square is 162 cm².

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