Geometry

Quadrilaterals

Easy

If two adjacent angles of a parallelogram are $(2x + 30)^\circ$ and $(3x - 15)^\circ$ . Then the value of x is:

✅ Correct Option: 3

Adjacent angles of a parallelogram sum to $180^\circ$ .

$(2x+30)+(3x-15)=180$

$5x+15=180$

$5x=165$

$x=33$ .

Note: The NTA answer key marks option B (39). Substituting $x=39$ gives $108^\circ+102^\circ=210^\circ$ , so we have solved using the correct geometric property which yields $x=33$ .

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(D) A rhombus, whose diagonals are 30 cm and 16 cm.

Arrange the above in ascending order.

Choose the correct answer from the options given below:

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If two adjacent angles of a parallelogram are (2x+30)∘(2x + 30)^\circ(2x+30)∘ and (3x−15)∘(3x - 15)^\circ(3x−15)∘. Then the value of x is:

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)

If two adjacent angles of a parallelogram are $(2x + 30)^\circ$ and $(3x - 15)^\circ$ . Then the value of x is: